5.3 The Fundamental Theorem of Calculus/23: Difference between revisions

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<math>\int_{0}^{1}x^\cfrac{4}{5}dx \\[2ex]
<math>\int_{0}^{1}x^\cfrac{4}{5}dx \\[2ex]


&= frac{5}\sqrt[5]{x^4}</math>
&=frac{5}\sqrt[5]{x^4}</math>

Revision as of 18:51, 25 August 2022

Failed to parse (syntax error): {\displaystyle \int_{0}^{1}x^\cfrac{4}{5}dx \\[2ex] &=frac{5}\sqrt[5]{x^4}}