5.3 The Fundamental Theorem of Calculus/23: Difference between revisions
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<math>\int_{0}^{1}x^\cfrac{4}{5}dx \\[2ex] | <math> | ||
\begin{align} | |||
\int_{0}^{1}x^\cfrac{4}{5}dx \\[2ex] | |||
&=frac{5}\sqrt[5]{x^4}</math> | &= frac{5}\sqrt[5]{x^4} | ||
\end{align} | |||
</math> | |||
Revision as of 18:56, 25 August 2022
![{\displaystyle {\begin{aligned}\int _{0}^{1}x^{\cfrac {4}{5}}dx\\[2ex]&=frac{5}{\sqrt[{5}]{x^{4}}}\end{aligned}}}](https://en.wikipedia.org/api/rest_v1/media/math/render/svg/166d73853b1f647f2e75e41c0a1d993cbf71782e)