5.3 The Fundamental Theorem of Calculus/41: Difference between revisions

Revision as of 19:30, 25 August 2022

$\int \limits _{0}^{\pi }f(x)dx\quad {\text{where}}\;f(x)={\begin{cases}sin(x)&0\leq x<\pi /2\\cos(x)&\pi /2\leq x\leq \pi \end{cases}}$

@@ Line 3: / Line 3: @@
 \int\limits_{0}^{\pi}f(x)dx
 \quad \text{where} \;
-f(x) = \begin{cases}
-& -1 \le x < 0 \\
+f(x) =
-- x^2 & \text{otherwise}
+  \begin{cases}
+     sin(x) & 0 \le x < \pi/2 \\
+     cos(x) & \pi/2 \le x \le \pi
    \end{cases}
 </math>