5.3 The Fundamental Theorem of Calculus/23: Difference between revisions
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&\int_{0}^{1}x^\cfrac{4}{5}dx \\[2ex] | &\int_{0}^{1}x^\cfrac{4}{5}dx \\[2ex] | ||
&\cfrac{5 \sqrt[5]{x^4}}{9} \\[2ex] | &\cfrac{5* \sqrt[5]{x^4}}{9} \\[2ex] | ||
&\cfrac{5 \sqrt[5]{x^4}}{9}\bigg|_{0}^{1} \\[2ex] | &\cfrac{5* \sqrt[5]{x^4}}{9}\bigg|_{0}^{1} \\[2ex] | ||
&\cfrac{5 \sqrt[1^5]{1^4}}{9}-\cfrac{5*0 \sqrt[5]{0^4}}{9} | &\cfrac{5* \sqrt[1^5]{1^4}}{9}-\cfrac{5*0 \sqrt[5]{0^4}}{9} | ||
\end{align} | \end{align} | ||
</math> | </math> | ||
Revision as of 19:15, 25 August 2022
![{\displaystyle {\begin{aligned}&\int _{0}^{1}x^{\cfrac {4}{5}}dx\\[2ex]&{\cfrac {5*{\sqrt[{5}]{x^{4}}}}{9}}\\[2ex]&{\cfrac {5*{\sqrt[{5}]{x^{4}}}}{9}}{\bigg |}_{0}^{1}\\[2ex]&{\cfrac {5*{\sqrt[{1^{5}}]{1^{4}}}}{9}}-{\cfrac {5*0{\sqrt[{5}]{0^{4}}}}{9}}\end{aligned}}}](https://en.wikipedia.org/api/rest_v1/media/math/render/svg/af126a4f6c98d3e4a36d96fa23808354b3ed2a8c)