5.3 The Fundamental Theorem of Calculus/10: Difference between revisions
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<math> g(r)=\int_{0}^{r}\sqrt{x^2+4} dx | <math> | ||
\begin{align} | |||
&\g(r)=\int_{0}^{r}\sqrt{x^2+4} dx | |||
&\frac{d}{dx}\int_{0}^{r}\sqrt{x^2+4}dx | |||
&\sqrt{x^2+4} | |||
\end{align} | |||
<math> |
Revision as of 19:18, 25 August 2022
<math> \begin{align}
&\g(r)=\int_{0}^{r}\sqrt{x^2+4} dx
&\frac{d}{dx}\int_{0}^{r}\sqrt{x^2+4}dx
&\sqrt{x^2+4}
\end{align} <math>