5.3 The Fundamental Theorem of Calculus/10: Difference between revisions
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\begin{align} | \begin{align} | ||
&\g(r)=\int_{0}^{r}\sqrt{x^2+4} dx \\[2ex] | &\g(r)=\int_{0}^{r}\sqrt{x^2+4}dx\\[2ex] | ||
&\frac{d}{dx}\int_{0}^{r}\sqrt{x^2+4}dx [2ex] | &\frac{d}{dx}\int_{0}^{r}\sqrt{x^2+4}dx\\[2ex] | ||
&\sqrt{x^2+4} | &\sqrt{x^2+4} | ||
Revision as of 19:20, 25 August 2022
<math> \begin{align}
&\g(r)=\int_{0}^{r}\sqrt{x^2+4}dx\\[2ex]
&\frac{d}{dx}\int_{0}^{r}\sqrt{x^2+4}dx\\[2ex]
&\sqrt{x^2+4}
\end{align} <math>