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<math>\left ( \frac{1}{2} \right )^n</math>
<math>\left ( \frac{1}{2} \right )^n</math>


<math>x=\frac{{\color{Blue}-b}\pm\sqrt{\color{Red}b^2-4ac}}{\color{Green}2a}</math>


<math>\sum_{m=1}^\infty\sum_{n=1}^\infty\frac{m^2 n}{3^m\left(m 3^n + n 3^m\right)}</math>
<math>\sum_{m=1}^\infty\sum_{n=1}^\infty\frac{m^2 n}{3^m\left(m 3^n + n 3^m\right)}</math>


<math>|\bar{z}| = |z|,
<math>|\bar{z}| = |z|,

Revision as of 19:21, 18 August 2022


 

 

 

 

(1)

Eq. 1


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