5.3 The Fundamental Theorem of Calculus/10: Difference between revisions
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&\g(r)=\int_{0}^{r}\sqrt{x^2+4}dx \\[2ex] | &\g(r)=\int_{0}^{r}\sqrt{x^2+4}dx \\[2ex] | ||
&\frac{d}{dx}\int_{0}^{r}\sqrt{x^2+4}dx \\[2ex] | &\frac{d}{dx}\int_{0}^{r}\sqrt{x^2+4}dx \\[2ex] | ||
Revision as of 19:24, 25 August 2022
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} &\g(r)=\int_{0}^{r}\sqrt{x^2+4}dx \\[2ex] &\frac{d}{dx}\int_{0}^{r}\sqrt{x^2+4}dx \\[2ex] \end{align} }