5.3 The Fundamental Theorem of Calculus/7: Difference between revisions
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<math>g(x)=\int_{1}^{x}\frac{1}{t^3+1}dt</math><br> | <math>g(x)=\int_{1}^{x}\frac{1}{t^3+1}dt</math><br> | ||
<math>\frac{d}{dx}\left[g(x)\right]=\frac{d}{dx}\left[\int_{1}^{x}\frac{1}{t^3+1}dt\right]</math>= | <math>\frac{d}{dx}\left[g(x)\right]=\frac{d}{dx}\left[\int_{1}^{x}\frac{1}{t^3+1}dt\right]</math>=(1)\left(\frac{1}{1+x^3}\right) | ||
Revision as of 19:38, 25 August 2022
=(1)\left(\frac{1}{1+x^3}\right)
![{\displaystyle {\frac {d}{dx}}\left[g(x)\right]={\frac {d}{dx}}\left[\int _{1}^{x}{\frac {1}{t^{3}+1}}dt\right]}](https://en.wikipedia.org/api/rest_v1/media/math/render/svg/f940df279b1920a77a743c787af515d9035eeeea)