5.3 The Fundamental Theorem of Calculus/33: Difference between revisions

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<math>h(x)=\int_{2}^{1/x}\arctan(t)dt</math>
<math>\int\limits_{2}^{1}\(2y+1)^dy
 
<math>\frac{d}{dx}\left[h(x)\right]=\frac{d}{dx}\left[\int_{2}^{1/x}\arctan(t)dt\right]<\math>

Revision as of 19:59, 25 August 2022

<math>\int\limits_{2}^{1}\(2y+1)^dy

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