5.3 The Fundamental Theorem of Calculus/9: Difference between revisions
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<math>g(y)= \int_{2}^{y}t^2\sin{(t)}dt | <math>g(y)= \int_{2}^{y}t^2\sin{(t)}dt | ||
<math>= 1\cdot(y^{2}sin{(y)})-0\cdot(2^{2}sin{(2)}) | </math>= 1\cdot(y^{2}sin{(y)})-0\cdot(2^{2}sin{(2)}) | ||
<math>= y^{2} sin{(y)} | </math>= y^{2} sin{(y)} | ||
</math> | </math> | ||
Revision as of 20:08, 25 August 2022
= 1\cdot(y^{2}sin{(y)})-0\cdot(2^{2}sin{(2)}) </math>= y^{2} sin{(y)} </math>
