6.2 Trigonometric Functions: Unit Circle Approach/48: Difference between revisions
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\begin{align} | \begin{align} | ||
\sin{\left(\frac{5\pi}{6}\right)} &= | \sin{\left(\frac{5\pi}{6}\right)} &= \frac{1}{2} & \csc{(t)} &= -\frac{2}{\sqrt{3}}\cdot\frac{\sqrt{3}}{\sqrt{3}}=\frac{2\sqrt{3}}{3}\\[2ex] | ||
\cos{\left(\frac{5\pi}{6}\right)} &= \frac{1}{2} & \sec{(t)} &= \frac{2}{1} = 2\\[2ex] | \cos{\left(\frac{5\pi}{6}\right)} &= \frac{1}{2} & \sec{(t)} &= \frac{2}{1} = 2\\[2ex] | ||
\tan{\left(\frac{5\pi}{6}\right)} &= \frac{-\frac{\sqrt{3}}{2}}{\frac{1}{2}} = -\frac{\sqrt{3}}{2}\cdot\frac{2}{1} = -\sqrt{3} & \cot{(t)} &= -\frac{1}{\sqrt{3}}=-\frac{1}{\sqrt{3}}\cdot\frac{\sqrt{3}}{\sqrt{3}}=\frac{\sqrt{3}}{3} \\[2ex] | \tan{\left(\frac{5\pi}{6}\right)} &= \frac{-\frac{\sqrt{3}}{2}}{\frac{1}{2}} = -\frac{\sqrt{3}}{2}\cdot\frac{2}{1} = -\sqrt{3} & \cot{(t)} &= -\frac{1}{\sqrt{3}}=-\frac{1}{\sqrt{3}}\cdot\frac{\sqrt{3}}{\sqrt{3}}=\frac{\sqrt{3}}{3} \\[2ex] |
Revision as of 22:24, 25 August 2022