5.3 The Fundamental Theorem of Calculus/9: Difference between revisions

From Burton Tech. Points Wiki
Jump to navigation Jump to search
No edit summary
No edit summary
Line 1: Line 1:
<math>g(y)= \int_{2}^{y}t^2\sin{(t)}dt</math><br>
<math>g(y)= \int_{2}^{y}t^2\sin{(t)}dt</math><br>
<math>1\cdot(y^{2}sin{(y)})-0\cdot(2^{2}sin{(2)})=  
<math>1\cdot(y^{2}\cdotsin{(y)})-0\cdot(2^{2}sin{(2)})=  
y^{2} sin{(y)}</math>
y^{2} sin{(y)}</math>

Revision as of 16:18, 26 August 2022


Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle 1\cdot(y^{2}\cdotsin{(y)})-0\cdot(2^{2}sin{(2)})= y^{2} sin{(y)}}