5.3 The Fundamental Theorem of Calculus/53: Difference between revisions

From Burton Tech. Points Wiki
Jump to navigation Jump to search
No edit summary
No edit summary
Line 1: Line 1:
<math>\int_{2x}^{3x}\frac{u^2-1}{u^2+1}du</math>
<math>\int_{2x}^{3x}\frac{u^2-1}{u^2+1}du</math>
<math>\frac{d}{dx}\left[int_{2x}^{3x}\frac{u^2-1}{u^2+1}du</math>
]

Revision as of 15:45, 26 August 2022

Failed to parse (syntax error): {\displaystyle \frac{d}{dx}\left[int_{2x}^{3x}\frac{u^2-1}{u^2+1}du} ]