6.2 Trigonometric Functions: Unit Circle Approach/112: Difference between revisions

Revision as of 17:26, 26 August 2022

$f(x)=\sin(x)$
$g(x)=\cos(x)$
$h(x)=2x$
$p(x)={\frac {x}{2}}$

$(h\circ p)(60^{\circ })=h(p(60^{\circ })$

Revision as of 17:25, 26 August 2022 (view source) Dvaezazizi@laalliance.org (talk \| contribs) No edit summary ← Older edit		Revision as of 17:26, 26 August 2022 (view source) Dvaezazizi@laalliance.org (talk \| contribs) No edit summary Newer edit →
Line 4:		Line 4:
	<math>p(x)=\frac{x}{2}</math><br><br>		<math>p(x)=\frac{x}{2}</math><br><br>

	<math>(h\circ p)(60^{\circ})</math>		<math>(h\circ p)(60^{\circ})=h(p(60^{\circ})</math>