6.2 Trigonometric Functions: Unit Circle Approach/112: Difference between revisions

Revision as of 17:28, 26 August 2022

$f(x)=\sin(x)$
$g(x)=\cos(x)$
$h(x)=2x$
$p(x)={\frac {x}{2}}$

$(h\circ p)(60^{\circ })=h(p(60^{\circ })=h({\frac {60^{\circ }}{2}})=h(30^{\circ })=2\cdot 30^{\circ }=60^{\circ }$

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	<math>p(x)=\frac{x}{2}</math><br><br>		<math>p(x)=\frac{x}{2}</math><br><br>

	<math>(h\circ p)(60^{\circ})=h(p(60^{\circ})</math>		<math>(h\circ p)(60^{\circ})=h(p(60^{\circ})=h(\frac{60^{\circ}}{2})=h(30^{\circ})=2\cdot30^{\circ}=60^{\circ}</math>