5.4 Indefinite Integrals and the Net Change Theorem/21: Difference between revisions
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(Created page with "<math>\int_{0}^{2}(6x^{2}-4x+5) dx</math>") |
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<math>\int_{0}^{2}(6x^{2}-4x+5) dx</math> | <math>\int_{0}^{2}(6x^{2}-4x+5) dx</math> = \frac{6x^{2+1}}{2+1}-\frac{4x^{1+2}}{1+2}+{5x}\bigg|_{0}^{2} | ||
Revision as of 19:13, 30 August 2022
= \frac{6x^{2+1}}{2+1}-\frac{4x^{1+2}}{1+2}+{5x}\bigg|_{0}^{2}
