5.4 Indefinite Integrals and the Net Change Theorem/3: Difference between revisions

From Burton Tech. Points Wiki
Jump to navigation Jump to search
No edit summary
No edit summary
Line 6: Line 6:
& \frac{d}{dx} {[\sin{x} - \frac{1}{3} \sin^3{x} +c]} \\[2ex]
& \frac{d}{dx} {[\sin{x} - \frac{1}{3} \sin^3{x} +c]} \\[2ex]


& {\cos{x} - \frac{1}{3}\cdot 3\sin{x^2} \cos{x} +0} \\[2ex]
& ={\cos{x} - \frac{1}{3}\cdot 3\sin{x^2} \cos{x} +0} \\[2ex]


& \cos{x} - \sin^2{x}\cos{x} \\[2ex]
& =\cos{x} - \sin^2{x}\cos{x} \\[2ex]


& = \cos^3{x}




\end{align}
\end{align}
</math>
</math>

Revision as of 19:30, 26 August 2022