6.2 Trigonometric Functions: Unit Circle Approach/57: Difference between revisions

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(Created page with "<math> -\frac {\pi}{6}= -30^{\circ}<\math><br> -90^{\circ}\cdot\frac{\pi}{180^{\circ}}=\frac{\cancel{2}\cdot \cancel{5} \cdot \cancel{3}\cdot \cancel{3}}{1}\cdot\frac{\pi}{{2}\cdot \cancel{2} \cdot \cancel{5} \cdot \cancel{3} \cdot \cancel{3}}\cdot{-1} = -\frac{\pi}{2} </math>")
 
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<math>
<math>
-\frac {\pi}{6}= -30^{\circ}<\math><br>
-\frac {\pi}{6}= -30^{\circ}</math><br>
 
<math> 360^{\circ} -30^{\circ} = 330^{\circ} = \frac{\sqrt{3}}{2} , -\frac{1}{2}</math><br>
-90^{\circ}\cdot\frac{\pi}{180^{\circ}}=\frac{\cancel{2}\cdot \cancel{5} \cdot \cancel{3}\cdot \cancel{3}}{1}\cdot\frac{\pi}{{2}\cdot \cancel{2} \cdot \cancel{5} \cdot \cancel{3} \cdot \cancel{3}}\cdot{-1}
<math>cos(-\frac {\pi}{6})= \frac{\frac{\sqrt{3}}{2}}{1} = \frac{\sqrt{3}}{2}</math><br>
= -\frac{\pi}{2}
<math>sin(-\frac {\pi}{6})= \frac{-\frac{1}{2}}{1} = -\frac{1}{2}</math><br>
 
<math>tan(-\frac {\pi}{6})= \frac{-\frac{1}{2}}{\frac{\sqrt{3}}{2}}\cdot(2) = -\frac{1}{\sqrt{3}} \cdot ({\sqrt{3}}) = \frac{-\sqrt{3}}{3}</math><br>
</math>
<math>sec(-\frac {\pi}{6})= \frac{1}{\frac{\sqrt{3}}{2}} \cdot (2) = \frac{2}{\sqrt{3}} \cdot (\sqrt{3}) = \frac {2\sqrt{3}}{3}</math><br>
<math>csc(-\frac {\pi}{6})= \frac{1}{-\frac{1}{2}} \cdot (2) = \frac{2}{-1} = -2 </math><br>
<math>cot(-\frac {\pi}{6})= \frac{\frac{\sqrt{3}}{2}}{-\frac{1}{2}} \cdot (2) = \frac{\frac{2}{\sqrt{3}}{-2} = -\sqrt{3}</math><br>

Revision as of 16:27, 29 August 2022








Failed to parse (syntax error): {\displaystyle cot(-\frac {\pi}{6})= \frac{\frac{\sqrt{3}}{2}}{-\frac{1}{2}} \cdot (2) = \frac{\frac{2}{\sqrt{3}}{-2} = -\sqrt{3}}

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