5.4 Indefinite Integrals and the Net Change Theorem/17: Difference between revisions

Revision as of 00:19, 29 August 2022

17) $\int {}{}1+tan^{2}x*dx$ = ${\frac {d}{dx}}(tan(x))$

@@ Line 1: / Line 1: @@
-)<math>\int{}{}1+tan^{2}x*dx</math>
+)<math>\int{}{}1+tan^{2}x*dx</math>=<math>\frac{d}{dx}(tan(x))</math>
-   <math>\int{}{}1+tan^{2}x*dx</math>
-  =<math>\frac{d}{dx}(tan(x))</math>