5.4 Indefinite Integrals and the Net Change Theorem/39

$\int _{1}^{64}{\frac {1+{\sqrt[{3}]{x}}}{\sqrt {x}}}dx$

$\int _{1}^{64}{\frac {1}{x^{1/2}}}$ + $\int _{1}^{64}{\frac {x^{1/3}}{x^{1/2}}}$

$\int _{1}^{64}x^{-1/2}+x^{1/3-1/2}$ = $\int _{1}^{64}x^{-1/2}+x^{-1/6}$

Add one to the exponents and divide by the new exponent

$\int _{1}^{64}{\frac {x^{1/2}}{1/2}}+{\frac {x^{5/6}}{\frac {5}{6}}}$