6.2 Trigonometric Functions: Unit Circle Approach/63: Difference between revisions

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(Undo revision 2768 by Jeremyr102216@students.laalliance.org (talk))
Tag: Undo
(Undo revision 2767 by Jeremyr102216@students.laalliance.org (talk))
Tag: Undo
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\begin{align}
\begin{align}


\sin{\left(\frac{-14\pi}{3}\right)} &= -\frac{\sqrt{3}}{2} & \csc{\left(\frac{-14\pi}{3}\right)} &= \frac{1}{\frac{\sqrt{3}}{2}}
\sin{\left(\frac{-14\pi}{3}\right)} &= -\frac{\sqrt{3}}{2} & \csc{\left(\frac{-14\pi}{3}\right)} &= \frac{2}{1}=2\\[2ex]
 
\cos{\left(\frac{-14\pi}{3}\right)} &= -\frac{1}{2} & \sec{\left(\frac{-14\pi}{3}\right)} &= \frac{{2}}{-\sqrt{3}}\cdot\frac{\sqrt{3}}{\sqrt{3}} = -\frac{2\sqrt{3}}{3}\\[2ex]  
\cos{\left(\frac{-14\pi}{3}\right)} &= -\frac{1}{2} & \sec{\left(\frac{-14\pi}{3}\right)} &= \frac{{2}}{-\sqrt{3}}\cdot\frac{\sqrt{3}}{\sqrt{3}} = -\frac{2\sqrt{3}}{3}\\[2ex]  



Revision as of 16:14, 29 August 2022