6.2 Trigonometric Functions: Unit Circle Approach/17: Difference between revisions

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\sin{(t)} &= \frac{\sqrt{2}}{2} & \csc{(t)} &= -\frac{2}{\sqrt{3}}\cdot\frac{\sqrt{3}}{\sqrt{3}}=\frac{2\sqrt{3}}{3}\\[2ex]
\sin{(t)} &= \frac{\sqrt{2}}{2} & \csc{(t)} &= -\frac{2}{\sqrt{3}}\cdot\frac{\sqrt{3}}{\sqrt{3}}=\frac{2\sqrt{3}}{3}\\[2ex]
\cos{(t)} &= -\frac{\sqrt{2}}{2}        & \sec{(t)} &= \frac{2}{1} = 2\\[2ex]  
\cos{(t)} &= -\frac{\sqrt{2}}{2}        & \sec{(t)} &= \frac{2}{1} = 2\\[2ex]  
\tan{(t)} &= \frac{\frac{\sqrt{2}}{2}}{-\frac{\sqrt{2}}{2}} \cdot{2} & \cot{(t)} &= -\frac{1}{\sqrt{3}}=-\frac{1}{\sqrt{3}}\cdot\frac{\sqrt{3}}{\sqrt{3}}=\frac{\sqrt{3}}{3} \\[2ex]
\tan{(t)} &= \frac{\frac{\sqrt{2}}{2}}{-\frac{\sqrt{2}}{2}} \cdot{2} = -\frac{\sqrt{2}} \sqrt{2} & \cot{(t)} &= -\frac{1}{\sqrt{3}}=-\frac{1}{\sqrt{3}}\cdot\frac{\sqrt{3}}{\sqrt{3}}=\frac{\sqrt{3}}{3} \\[2ex]


\end{align}
\end{align}
</math>
</math>

Revision as of 17:52, 30 August 2022