5.5 The Substitution Rule/51: Difference between revisions

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& \int {t^{25}} dt \\[2ex]
& \int {t^{25}} dt \\[2ex]


& \cfrac{t^{25}} {26}
& \cfrac{t^{25}} {26} \\[2ex]
 
& \cfrac ({x-1)^{26} {26}\bigg|_{0}^{2}





Revision as of 17:23, 31 August 2022

Failed to parse (unknown function "\begin{align}"): {\displaystyle \begin{align} & \int_{0}^{2} ({x-1})^{25} dx \\[2ex] & \int {t^{25}} dt \\[2ex] & \cfrac{t^{25}} {26} \\[2ex] & \cfrac ({x-1)^{26} {26}\bigg|_{0}^{2} \end{align} }