5.5 The Substitution Rule/51: Difference between revisions

From Burton Tech. Points Wiki
Jump to navigation Jump to search
No edit summary
No edit summary
Line 8: Line 8:
& \cfrac{t^{25}} {26} \\[2ex]
& \cfrac{t^{25}} {26} \\[2ex]


& \cfrac{x-1}^{26}\bigg|_{0}^{2}
& \frac{x-1}^{26}\bigg|_{0}^{2}





Revision as of 17:27, 31 August 2022

Failed to parse (unknown function "\begin{align}"): {\displaystyle \begin{align} & \int_{0}^{2} ({x-1})^{25} dx \\[2ex] & \int {t^{25}} dt \\[2ex] & \cfrac{t^{25}} {26} \\[2ex] & \frac{x-1}^{26}\bigg|_{0}^{2} \end{align} }