5.5 The Substitution Rule/51: Difference between revisions

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& \cfrac{x-1^{26}} {26}\bigg|_{0}^{2} \\[2ex]
& \cfrac{x-1^{26}} {26}\bigg|_{0}^{2} \\[2ex]


& \cfrac{2-1^26}} {26} + \cfrac {0-1^26}} {26} \\[2ex]
& \cfrac{2-1^26}} {26}  


&= 0
&= 0

Revision as of 17:31, 31 August 2022

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} & \int_{0}^{2} ({x-1})^{25} dx \\[2ex] & \int {t^{25}} dt \\[2ex] & \cfrac{t^{25}} {26} \\[2ex] & \cfrac{x-1^{26}} {26}\bigg|_{0}^{2} \\[2ex] & \cfrac{2-1^26}} {26} &= 0 \end{align} }