5.5 The Substitution Rule/51

${\begin{aligned}&\int _{0}^{2}({x-1})^{25}dx\\[2ex]&\int {t^{25}}dt\\[2ex]&{\cfrac {t^{25}}{26}}\\[2ex]&{\cfrac {(x-1)^{26}}{26}}{\bigg |}_{0}^{2}\\[2ex]&{\cfrac {(2-1)^{26}}{26}}-{\cfrac {(0-1)^{26}}{26}}\\[2ex]&=0\end{aligned}}$