6.2 Trigonometric Functions: Unit Circle Approach/49: Difference between revisions

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<math>\sin 210 \frac{2\pi}{3} \Rightarrow \left(-\frac{1}{2}, \frac{\sqrt{3}}{2}\right)</math><br><br>


<math>
\begin{align}
\sin{\left(\frac{2\pi}{3}\right)} &= \frac{\sqrt{3}}{2} & \csc{\left(\frac{2\pi}{3}\right)} &= \frac{{1}} \frac{\sqrt{3}}{2} \cdot{2} = \frac{2}{\sqrt{3}} \cdot{\sqrt{3}} = \frac{2\sqrt{3}}{3} \\[2ex]
\cos{\left(\frac{2\pi}{3}\right)} &= -\frac{1}{2} & \sec{\left(\frac{2\pi}{3}\right)} &= \frac{1}{-\frac{1}{2}} \cdot{2} = -\frac{2}{1} = -2 \\[2ex]
\tan{\left(\frac{2\pi}{3}\right)} &= \frac{\frac{\sqrt{3}}{2}}{-\frac{1}{2}} \cdot{2} = -\frac{\sqrt{3}}{1} = -\sqrt{3}
& \cot{\left(\frac{2\pi}{3}\right)} &= -\frac{\sqrt{3}}{1}= -\sqrt{3} \\[2ex]
\end{align}
</math>

Revision as of 20:55, 1 September 2022