5.5 The Substitution Rule/19: Difference between revisions

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& = \ \frac{u^{2+1}}{2+1}du \ = \ \frac{1}{3}u^3+C \\[2ex]
& = \ \frac{u^{2+1}}{2+1}du \ = \ \frac{1}{3}u^3+C \\[2ex]


u=\ln(x)
& u=\ln(x)
du=\frac{1}{x}dx
& du=\frac{1}{x}dx
du=\frac{dx}{x}
 


& = \ \frac{1}{3}(\ln(x))^3+C
& = \ \frac{1}{3}(\ln(x))^3+C

Revision as of 06:58, 3 September 2022