5.5 The Substitution Rule/15: Difference between revisions
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\begin{align} | \begin{align} | ||
let u &=\pi t \\[2ex] | let \hspace u &=\pi t \\[2ex] | ||
du &= \pi dx \\[2ex] | du &= \pi dx \\[2ex] | ||
\frac{1}{\pi}du &= dx | \frac{1}{\pi}du &= dx |
Revision as of 04:36, 5 September 2022
Failed to parse (unknown function "\hspace"): {\displaystyle \begin{align} let \hspace u &=\pi t \\[2ex] du &= \pi dx \\[2ex] \frac{1}{\pi}du &= dx \end{align} }