5.5 The Substitution Rule/69: Difference between revisions

Revision as of 15:45, 6 September 2022

${\begin{aligned}\int _{0}^{1}\left({\frac {e^{z}+1}{e^{z}+z}}\right)&=\int _{0}^{1}f(x)\end{aligned}}$

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 <math>
 \begin{align}
-\int_{0}^{1} \left(\frac{e^z + z}{e^z + 1}\right) &= \int_{0}^{1} f(x)
+\int_{0}^{1} \left(\frac{e^z + 1}{e^z + z}\right) &= \int_{0}^{1} f(x)
 \end{align}
 </math>