6.2 Trigonometric Functions: Unit Circle Approach/61: Difference between revisions

From Burton Tech. Points Wiki
Jump to navigation Jump to search
No edit summary
No edit summary
Line 1: Line 1:
<math> \frac{5\pi}{6}
<math> \frac{5\pi}{6}
\sin({\frac{5\pi}{6}})=1 \sec{\frac{5\pi}{6}}=\frac{1}{1}=1
\sin({\frac{5\pi}{6}})=1 \sec({\frac{5\pi}{6}})=\frac{1}{1}=1
\cos{\frac{5\pi}{6}}=0 \csc{\frac{5\pi}{6}}=\frac{1}{0}=Undefined
\cos({\frac{5\pi}{6}})=0 \csc({\frac{5\pi}{6}})=\frac{1}{0}=Undefined
\tan{\frac{5\pi}{6}}=\frac{1}{0}=Undefind \cot{\frac{5\pi}{6}}=\frac{0}{1}=0
\tan({\frac{5\pi}{6}})=\frac{1}{0}=Undefind \cot({\frac{5\pi}{6}})=\frac{0}{1}=0
</math>
</math>

Revision as of 16:19, 6 September 2022

Retrieved from "https://wiki.btechp.org/index.php?title=6.2_Trigonometric_Functions:_Unit_Circle_Approach/61&oldid=3375"