6.2 Trigonometric Functions: Unit Circle Approach/109: Difference between revisions

Revision as of 15:40, 8 September 2022

$f(x)=\sin(x)$
$g(x)=\cos(x)$
$h(x)=2x$
$p(x)={\frac {x}{2}}$

$(f\cdot g)({\frac {3\pi }{4}})=f(g({\frac {3\pi }{4}})=h\left({\frac {30^{\circ }}{2}}\right)=h(15^{\circ })=2\cdot 15^{\circ }=30^{\circ }$

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	<math>p(x)=\frac{x}{2}</math><br><br>		<math>p(x)=\frac{x}{2}</math><br><br>

	<math>(f\cdot g)(\frac{3\pi}{4})=h(p(~~30^~~{\~~circ~~})=h\left(\frac{30^{\circ}}{2}\right)=h(15^{\circ})=2\cdot15^{\circ}=30^{\circ}</math>		<math>(f\cdot g)(\frac{3\pi}{4})=f(g(\frac{3\pi}{4})=h\left(\frac{30^{\circ}}{2}\right)=h(15^{\circ})=2\cdot15^{\circ}=30^{\circ}</math>