6.2 Volumes/25: Difference between revisions

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<math>
<math>
R + f(y) = 1 \arrow R = 1-f(y)
R + f(y) = 1 \arrow R = 1-f(y)
r = 1 \\
r = 1  
</math>
</math>



Revision as of 02:59, 12 September 2022

Failed to parse (unknown function "\arrow"): {\displaystyle R + f(y) = 1 \arrow R = 1-f(y) r = 1 }