5.4 Indefinite Integrals and the Net Change Theorem/17: Difference between revisions

Revision as of 17:41, 13 September 2022

$\int _{}^{}1+tan^{2}xdx=\int _{}^{}1+{\frac {sin^{2}x}{cos^{2}x}}dx=\int _{}^{}{\frac {cos^{2}x+sin^{2}x}{cos^{2}x}}dx\cos ^{2}x+sin^{2}x=1\int _{}^{}{\frac {1}{cos^{2}x}}dx=\int _{}^{}\sec ^{2}xdx=tanx+C$

Revision as of 17:41, 13 September 2022 (view source) Dvaezazizi@laalliance.org (talk \| contribs) No edit summary ← Older edit		Revision as of 17:41, 13 September 2022 (view source) Dvaezazizi@laalliance.org (talk \| contribs) No edit summary Newer edit →
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	~~17)~~<math>\int_{}^{}1+tan^2xdx =		<math>\int_{}^{}1+tan^2xdx =

	\int_{}^{}1+\frac{sin^2x}{cos^2x}dx =		\int_{}^{}1+\frac{sin^2x}{cos^2x}dx =

5.4 Indefinite Integrals and the Net Change Theorem/17: Difference between revisions

Revision as of 17:41, 13 September 2022

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