5.4 Indefinite Integrals and the Net Change Theorem/27: Difference between revisions

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\begin{align}
\begin{align}


\int_{1}^{4}\sqrt{t}(1+t)dt =\int_{1}^{4}\left(t^{\frac{1}{2}}+t^{\frac{3}{2}}\right)dt
\int_{1}^{4}\sqrt{t}(1+t)dt &=\int_{1}^{4}\left(t^{\frac{1}{2}}+t^{\frac{3}{2}}\right)dt \\[2ex]


=\frac{2(t)^{3/2}}{3}+\frac{2(t)^{5/2}}{5}
&=\frac{2(t)^{3/2}}{3}+\frac{2(t)^{5/2}}{5}


=\frac{2(t)^{3/2}}{3}+\frac{2(t)^{5/2}}{5}\bigg|_{1}^{4}
=\frac{2(t)^{3/2}}{3}+\frac{2(t)^{5/2}}{5}\bigg|_{1}^{4}

Revision as of 15:08, 21 September 2022