5.4 Indefinite Integrals and the Net Change Theorem/33: Difference between revisions

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&= 2\sqrt{5}\sqrt{4}-2\sqrt{5}{\sqrt{1}} \\[2ex]
&= 2\sqrt{5}\sqrt{4}-2\sqrt{5}{\sqrt{1}} \\[2ex]
   
   
&= 2\sqrt{20}-2\sqrt{5} = 4\sqrt{5}-2\sqrt{5} = 2\sqrt{5}
&= 4\sqrt{5}-2\sqrt{5} \\[2ex]
 
&= 2\sqrt{5}
\end{align}
\end{align}
</math>
</math>

Revision as of 15:29, 21 September 2022