5.5 The Substitution Rule/61: Difference between revisions
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New upper limit: <math>\ | New upper limit: <math>\27 = 1+2(13)</math><br> | ||
New lower limit: <math> | New lower limit: <math>1 = 1+2(0)</math> | ||
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\begin{align} | \begin{align} | ||
\int_{0}^{13}\frac{ | \int_{0}^{13}\frac{1}{\sqrt[3]{(1+2x)^2}}\,dx &= \int_{0}^{13}\frac{1}{\sqrt[3]{(1+2x)^2}}\,(dx) \\[2ex] | ||
&= \int_{ | &= \int_{1}^{27} \int_{1}^{27}\frac{1}{\sqrt[3]{(1+2x)^2}}\left(\frac{1}{2}du\right) = \frac{1}{2}\int_{0}^{\pi} \cos{(u)}du \\[2ex] | ||
&= \frac{1}{2}\sin{(u)}\bigg|_{0}^{\pi} \\[2ex] | &= \frac{1}{2}\sin{(u)}\bigg|_{0}^{\pi} \\[2ex] | ||
&= \frac{1}{2}\sin{(\pi)} - \frac{1}{2}\sin{(0)} \\[2ex] | &= \frac{1}{2}\sin{(\pi)} - \frac{1}{2}\sin{(0)} \\[2ex] |
Revision as of 04:00, 22 September 2022
= = = = = = = = = \\[2ex]
New upper limit: Failed to parse (syntax error): {\displaystyle \27 = 1+2(13)}
New lower limit: