5.4 Indefinite Integrals and the Net Change Theorem/31: Difference between revisions

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&= \left(\frac{3x^{\frac{7}{3}}}{7}+\frac{4x^{\frac{9}{4}}}{9}\right)\Bigg|_{0}^{1} \\[2ex]
&= \left(\frac{3x^{\frac{7}{3}}}{7}+\frac{4x^{\frac{9}{4}}}{9}\right)\Bigg|_{0}^{1} \\[2ex]


&= \frac{3}{7}+\frac{4}{9} = \frac{27+28}{7*9} = \frac{55}{63}
&= \frac{3}{7}+\frac{4}{9} = \frac{27+28}{7\cdot9} = \frac{55}{63}


\end{align}
\end{align}
</math>
</math>

Latest revision as of 19:07, 22 September 2022