Example Page: Difference between revisions

Revision as of 18:00, 18 August 2022

$f(x)=x^{2}$

$\sum _{m=1}^{\infty }\sum _{n=1}^{\infty }{\frac {m^{2}n}{3^{m}\left(m3^{n}+n3^{m}\right)}}$

$|{\bar {z}}|=|z|,|({\bar {z}})^{n}|=|z|^{n},\arg(z^{n})=n\arg(z)$

$f(x)={\begin{cases}1&-1\leq x<0\\{\frac {1}{2}}&x=0\\1-x^{2}&{\text{otherwise}}\end{cases}}$

testing

@@ Line 1: / Line 1: @@
 <math> f(x)=x^2</math>
+<math>\sum_{m=1}^\infty\sum_{n=1}^\infty\frac{m^2 n}{3^m\left(m 3^n + n 3^m\right)}</math>
-<math>\sum_{m=1}^\infty\sum_{n=1}^\infty\frac{m^2 n}{3^m\left(m 3^n + n 3^m\right)}</math>
-<br>
 <math>|\bar{z}| = |z|,
 |(\bar{z})^n| = |z|^n,
 \arg(z^n) = n \arg(z)</math>
-<br>
 <math>f(x) =
    \begin{cases}