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\arg(z^n) = n \arg(z)</math>
\arg(z^n) = n \arg(z)</math>


 
{{NumBlk|:|<math>x^2 + y^2 + z^2 = 1</math>|{{EquationRef|1}}}}


<math>f(x) =
<math>f(x) =

Revision as of 18:48, 18 August 2022



 

 

 

 

(1)

testing