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|(\bar{z})^n| = |z|^n,
|(\bar{z})^n| = |z|^n,
\arg(z^n) = n \arg(z)</math>
\arg(z^n) = n \arg(z)</math>


{{NumBlk|:|<math>x^2 + y^2 + z^2 = 1</math>|{{EquationRef|1}}}}
{{NumBlk|:|<math>x^2 + y^2 + z^2 = 1</math>|{{EquationRef|1}}}}
:{{EquationRef|Eq. 1}} <math>x^2+x+1=0</math>


<math>f(x) =
<math>f(x) =

Revision as of 19:14, 18 August 2022




 

 

 

 

(1)

Eq. 1


testing