5.3 The Fundamental Theorem of Calculus/23: Difference between revisions

Revision as of 18:58, 25 August 2022

${\begin{aligned}&\int _{0}^{1}x^{\cfrac {4}{5}}dx\\[2ex]&=frac{5}{\sqrt[{5}]{x^{4}}}\end{aligned}}$

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	&=\int_{0}^{1}x^\cfrac{4}{5}dx \\[2ex]		&\int_{0}^{1}x^\cfrac{4}{5}dx \\[2ex]

	&= frac{5}\sqrt[5]{x^4}		&= frac{5}\sqrt[5]{x^4}