5.3 The Fundamental Theorem of Calculus/39: Difference between revisions

Revision as of 19:13, 25 August 2022

1. $\int \limits _{-1}^{1}e^{u+1}du$ = $\int \limits _{-1}^{1}e^{u}e^{1}du$ = $e^{1}\int \limits _{-1}^{1}e^{u}$ = $e^{1}e^{u}{\bigg |}_{-1}^{1}$

Revision as of 19:13, 25 August 2022 (view source) Debbier70425@students.laalliance.org (talk \| contribs) No edit summary ← Older edit		Revision as of 19:13, 25 August 2022 (view source) Debbier70425@students.laalliance.org (talk \| contribs) No edit summary Newer edit →
Line 1:		Line 1:
	1.<math>\int\limits_{-1}^{1}e^{u+1} du</math> = <math>\int\limits_{-1}^{1}e^{u}e^{1} du</math> = <math>e^{1}\int\limits_{-1}^{1}e^{u}</math>		1.<math>\int\limits_{-1}^{1}e^{u+1} du</math> = <math>\int\limits_{-1}^{1}e^{u}e^{1} du</math> = <math>e^{1}\int\limits_{-1}^{1}e^{u}</math> = <math>e^{1}e^{u}\bigg\|_{-1}^{1}</math>
	= <math>e^{1}e^{u}\bigg\|_{-1}^{1}</math>