5.3 The Fundamental Theorem of Calculus/19: Difference between revisions
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<math | <math\begin{align}\int\limits_{-1}^{2}(x^3-2x) dx</math>&=\frac{x^4}{4}-\frac{2x^2}{2}\bigg|_{-1}^{2}</math> | ||
\begin{align} | |||
\int\limits_{-1}^{2}(x^3-2x) dx</math>&=\frac{x^4}{4}-\frac{2x^2}{2}\bigg|_{-1}^{2} | |||
</math> | |||
Revision as of 19:20, 25 August 2022
<math\begin{align}\int\limits_{-1}^{2}(x^3-2x) dx</math>&=\frac{x^4}{4}-\frac{2x^2}{2}\bigg|_{-1}^{2}</math>