5.3 The Fundamental Theorem of Calculus/15: Difference between revisions

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\begin{align}
\begin{align}


y=\int_{0}^{tan(x)}\sqrt{t+\sqrt t}\,dt =\sqrt{tan(x)+\sqrt tan(x)}\,&sdot\sec^{2}(x)
y=\int_{0}^{tan(x)}\sqrt{t+\sqrt t}\,dt =\sqrt{tan(x)+\sqrt tan(x)}\cdot\sec^{2}(x)


\end{align}
\end{align}
</math>
</math>

Revision as of 19:24, 25 August 2022

Use part 1 of the FTC to find the derivative of the function: