5.3 The Fundamental Theorem of Calculus/19: Difference between revisions
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<math>\begin{align}int_{-1}^{2}(x^3-2x)dx &=\frac{x^4}{4}-\frac{2x^2}{2}\Bigg|_{-1}^{2}\end{align}</math> | <math>\begin{align}\int_{-1}^{2}\(x^3-2x)dx &=\frac{x^4}{4}-\frac{2x^2}{2}\Bigg|_{-1}^{2}\end{align}</math> | ||
Revision as of 19:26, 25 August 2022
Failed to parse (unknown function "\begin{align}"): {\displaystyle \begin{align}\int_{-1}^{2}\(x^3-2x)dx &=\frac{x^4}{4}-\frac{2x^2}{2}\Bigg|_{-1}^{2}\end{align}}