5.3 The Fundamental Theorem of Calculus/23: Difference between revisions

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&\cfrac{5\cdot \sqrt[5]{x^4}}{9}\bigg|_{0}^{1} \\[2ex]
&\cfrac{5\cdot \sqrt[5]{x^4}}{9}\bigg|_{0}^{1} \\[2ex]


&\cfrac{5\cdot \sqrt[1^5]{1^4}}{9}-\cfrac{5*0 \sqrt[5]{0^4}}{9} \\[2ex]
&\cfrac{5\cdot \sqrt[1^5]{1^4}}{9}-\cfrac{5\cdot0 \sqrt[5]{0^4}}{9} \\[2ex]


&=\cfrac{5}{9}
&=\cfrac{5}{9}

Revision as of 19:27, 25 August 2022