5.3 The Fundamental Theorem of Calculus/23: Difference between revisions
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&\cfrac{5\cdot \sqrt[5]{x^4}}{9}\bigg|_{0}^{1} \\[2ex] | &\cfrac{5\cdot \sqrt[5]{x^4}}{9}\bigg|_{0}^{1} \\[2ex] | ||
&\cfrac{5\cdot \sqrt[1^5]{1^4}}{9}-\cfrac{5 | &\cfrac{5\cdot \sqrt[1^5]{1^4}}{9}-\cfrac{5\cdot0 \sqrt[5]{0^4}}{9} \\[2ex] | ||
&=\cfrac{5}{9} | &=\cfrac{5}{9} |
Revision as of 19:27, 25 August 2022