5.3 The Fundamental Theorem of Calculus/7: Difference between revisions
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<math>\int_{1}^{x}\frac{1}{t^3+1}dt</math><br> | <math>\g(x)=int_{1}^{x}\frac{1}{t^3+1}dt</math><br> | ||
<math>g'(x)=(1)\left(\frac{1}{1+x^3}\right)</math> | <math>g'(x)=(1)\left(\frac{1}{1+x^3}\right)</math> | ||
Revision as of 19:29, 25 August 2022
Failed to parse (unknown function "\g"): {\displaystyle \g(x)=int_{1}^{x}\frac{1}{t^3+1}dt}
