6.2 Trigonometric Functions: Unit Circle Approach/48: Difference between revisions

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(Created page with "<math>\frac{5\pi}{6} \Rightarrow (\frac{-\sqrt{3}}{2}, \frac{1}{2})</math> <math> \begin{align} \sin{(t)} &= -\frac{\sqrt{3}}{2} & \csc{(t)} &= -\frac{2}{\sqrt{3}}\cdot\frac{\sqrt{3}}{\sqrt{3}}=\frac{2\sqrt{3}}{3}\\[2ex] \cos{(t)} &= \frac{1}{2} & \sec{(t)} &= \frac{2}{1} = 2\\[2ex] \tan{(t)} &= \frac{-\frac{\sqrt{3}}{2}}{\frac{1}{2}} = -\frac{\sqrt{3}}{2}\cdot\frac{2}{1} = -\sqrt{3} & \cot{(t)} &= -\frac{1}{\sqrt{3}}=-\frac{1}{\sqrt{3}}\cdot\frac{\sqrt{3}}{\s...")
 
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<math>\frac{5\pi}{6} \Rightarrow (\frac{-\sqrt{3}}{2}, \frac{1}{2})</math>
<math>\frac{5\pi}{6} \Rightarrow \left(\frac{-\sqrt{3}}{2}, \frac{1}{2}\right)</math>


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Revision as of 22:23, 25 August 2022